Agoose is flying south for the winter at a constant speed. keep in mind that one mile is 1.61 km, and one pound is 454 g. the goose has a mass of 20.1 lb and is flying at 9.60 miles/h. what is the kinetic energy of the goose in joules?

kinetic energy =  84.0260 joules

Explanation:

given data

one mile = 1.61 km

one pound = 454 g

mass = 20.1 lb = 9.1172 kg

flying velocity = 9.60 miles/h = 9.60 × 1.61 × = 4.2933 m/s  

solution

we get here kinetic energy that is express as

kinetic energy = 0.5 × m × v²   .........................1

put here value and we get

kinetic energy = 0.5 × 9.1172 × 4.2933²

kinetic energy =  84.0260 joules

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

cock topography

the study of the surface of a large voluptuous cock.

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cock topography!