Agraduated cylinder contains 18.0ml of water. what is the new water level after 35.6g of silver metal with a density of 10.5 g/ml is submerged in the water?

2.a thermometer containing 8.3g of mercury has broken. if mercury has a density of 13.6 g/ml what volumn spilled.

3. a fish tank holds 345gal of water. using the density of 1.0 g/ml for water, determine the number of pounds of water in the fish tank.

The answer to your question is

1.- Volume = 3.4 ml

2.- Volume = 0.61 ml

3.- Mass = 2872.8 pounds

Explanation:

Problem 1

Volume = 18 ml

mass = 35.6 g

density = 10.5 g/ml

Process

1.- Calculate the volume of silver

Formula

solve for volume

Substitution

volume = 3.4 ml

2.- Problem 2

Total volume = ?

Volume = 18 + 3.4

Volume = 21.4 ml

Data

mass = 8.3 g

density = 13.6 g(ml

volume = ?

Formula

Solve for volume

Substitution

Result

volume = 0.61 ml

3.- Problem 3

Data

volume = 345 gal

density = 1 g/ml

mass = ?

Formula

Solve for mass

mass = density x volume

Covert gal to ml

                            1 gal --------------- 3785 ml

                         345 gal -------------  x

                            x = (345 x 3785) / 1

                            x = 1305825 ml

Substitution

mass = 1 x 1305825

mass = 1305825 g

Convert g to pounds

                        1 g ------------------- 0.0022 pounds

              1305825 g ----------------   x

                        x = (1305825 x 0.0022)

                        x = 2872.8 pounds

it is the most commonly accepted one