For the reaction below, calculate the number of moles of nh3 that would be formed when 5.5 moles of n2h4 reacts completely: 3n2h4 --> 4nh3 + n2

7.33 moles of NH₃ are produced in the reaction.

Explanation:

The reaction is this:

3 N₂H₄  →  4NH₃ +  N₂

Ratio is 3:4

So 3 moles of N₂H₄ were needed to produce 4 moles of ammonia

5.5 moles of N₂H₄ would produce (5.5  . 4 ) / 3 = 7.33 moles of NH₃

is there multiple choice answers?