Consider the reaction:
2al(s) + fe2o3(s) - al2o3(s) + 2fe(s)
the ah, for fe2o3(s) = -824.3 kj/mole. the ah, for al2o3(s) = -1675.7 kj/mole.
finish the equation.
ahxn = [(1)
c
y
kj/mole) + (2)
y kj/mole)] - [(1)
kj/mole) + (2) (
kj/mole)]

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

h