Fe₃o₄ reacts with co according to the equation
fe₃o₄ + co --> fe + co₂ (unbalanced)
if 478.9 g fe₃o₄ is reacted with excess co, what mass of co₂ will be produced assuming 100% yield?
1. 91.02 g co₂
2. 182.05 g co₂
3. 364.1 g co₂
4. none of these
5. 273.1 g co₂

Option 3.

364.1 g of CO₂ are produced by the reaction

Explanation:

Let's verify the balance equation for this reaction:

Fe₃O₄  +   4 CO  →  3 Fe   +   4CO₂

Let's convert the mass of Fe₃O₄ to moles (mass / molar mass)

478.9 g / 231.55 g/mol  = 2.07 moles

Ratio is 1:4, so let's make a rule of three to determine the moles of CO₂ produced and then its mass.

1 mol of Fe₃O₄ is needed to produce 4 moles of CO₂

Then, 2.07 moles of Fe₃O₄ will produce (2.07  .4) /1 = 8.27 moles of CO₂.

Molar mass . moles = mass

44 g/mol . 8.27 mol = 364 g of CO₂

these nuts

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