Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. the heat of combustion of cyclopropane, c3h6, is 499.8 kcal/mol. write a balanced equation for the complete combustion of cyclopropane. how much energy is released during the complete combustion of 497 grams of cyclopropane? kcal

The complete combustion of cyclopropane is:

2C₃H₆  +  9O₂  →  6CO₂  +  6H₂O

5914.3kcal are realeased in the  combustion of 497 g of cyclopropane

Explanation:

Heat of combustion = 499.8 kcal/mol

This data means that 1 mol of C₃H₆ release 499.8 kcal.

Let's convert the mass to moles (mass / molar mass)

497 g / 42g/mol = 11.83 moles

Let's make a rule of three:

1 mol 499.8

11.83 moles (11.83  .499.8)/1 =5914.3kcal

sry but any answer choices

answer: semi-infinite solid initially at a uniform temperature of 400 ◦c is cooled at its surface by convection. the cooling fluid at a constant temperature of 200 ◦c has a convective coefficient (ha) of 250 w/m2.k. the physical properties of the solid: k = 20 w/m.k and α = 4 * 10-5  m2/s. using δx = 0.04 m and δt = 10 s. write the finite difference equations describing the transient heat transfer of the first five δx and the temperature profile after 30 s.