Chemistry, 24.01.2020 07:31 rodriguezzamyy

Acompound is composed of 72% iron and 27.6% oxygen. what is the empirical formula?

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Answer from: nehamaan503

A compound is composed of 72% iron and 27.6% oxygen, the empirical formula is - Fe_3O_4

we need to convert the given percent composition to grams, then convert the grams to moles by using the molar masses of the elements.

pick a 100-g sample of this unknown compound.According to the given percent composition, this sample will contain

72% = Fe = 72 g

27.6% = O = 27.6 g

Now, use the molar masses of the two elements to determine the number of moles of each you have in this sample.

For Fe = $\frac{ 72 \times 1\ mole\ of\ Fe}{55.84}$ = 1.534 moles Fe

for O = $\frac{27.6 \times 1\ mole\ of\ O}{16}$ = 2.045 moles O

To get the mole ratio that exists between the elements in the compound, divide all values by the smallest one. This will get youTo do that, divide both values by the smallest one:

For Fe: $\frac{1.534}{1.534}$ = 1

For O: $\frac{2.045}{1.534}$ = 1.33

To get the smallest whole number ratio that exists between the two elements, multiply both values by 3 . This will help you get rid of the decimal fraction for oxygen.

The empirical formula of the iron oxide will thus be

Thus, A compound is composed of 72% iron and 27.6% oxygen, the empirical formula is - Fe_3O_4

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Answer from: thompsonmark0616

The empirical formula is $Fe_{3}O_{4}$ .

Explanation:

Empirical formula is the easiest way of represent a chemical compound with representing the ratio of each element present in the compound. For finding the empirical formula, first we have to know the molar mass present in the given percentage of elements.

As we know that the molar mass of iron is 55.8 g/mol and oxygen in 16 g/mol, then dividing the percentage of elements given with their respective molar mass will give us the moles present in this composition.So,

$\frac{72}{56}=1.29 \text { moles of } F e$

$\frac{27.6}{16}=1.725 \text { moles of } 0$

Now the least among the two is 1.29, so we have to divide the moles of Fe and O with this to determine the ratio of each element. So, we are getting the ratio of 1:1.3, then if we multiply it by 3, we can get integer terms as 3:4. Thus, we obtained that Fe is 3 and O is 4. So the empirical formula will be $Fe_{3}O_{4}$ .

Answer from: Quest

asking the goog might u get an answer

Answer from: Quest

No is the answer to the question

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