A8-kg plastic tank that has a volume of 0.18 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.

1.84 × 10³ N

Explanation:

To determine the weight of the system, we will determine its mass which is equal to the sum of the masses of the plastic tank (8 kg) and the water.

We have 0.18 m³ of water with a density of 1000 kg/m³. Its mass is:

0.18 m³ × 1000 kg/m³ = 180 kg

The mass of the system is 180 kg + 8 kg = 188 kg.

We can find the weight (w) of the system using Newton's second law of motion.

w = m × g = 188 kg × 9.81 m/s² = 1.84 × 10³ N

where

g is the gravity

the ratio of the conjugate base to the acid required to attain the desired ph.

i believe the answer is three water molecules