21.6 j of energy are used to heat a 2.0 g piece of iron from 5.0oc to 29.0oc. what is the experimental specific heat capacity of iron in j/ (g . oc) ?

answer quickly !

0.45 J / g °C

Explanation: solution attached.

Heat is equal to the product of mass, specific heat and change in temperature.

Q= mc∆T

Derive the equation to find c

c = Q / m∆T substitute the values

c = 21.6 J / 2.0g ( 24°C - 5°C)

c = 0.45 J / g ° C

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in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm