Raoult's law accounts for the fact that the vapor pressure of a solvent will decrease as the mole fraction of the solvent is decreased. in considering the mole fraction, it is important to consider the total moles of dissolved particles. remember: a particle can be a dissolved molecule or ion. which aqueous solutions would have the lowest vapor pressure

Raoult's law accounts for the fact that the vapor pressure of a solvent will decrease as the mole fraction of the solvent is decreased. In considering the mole fraction, it is important to consider the total moles of dissolved particles. Remember: a particle can be a dissolved molecule or ion. Which aqueous solutions would have the lowest vapor pressure.

0.1 M , 0.1 M ,  0.1 M ,  0.1 M and  0.1 M

0.1 M

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

where,

= relative lowering in vapor pressure

i = Van'T Hoff factor  

= mole fraction of solute  

1. For 0.1 M

, i= 2 as it is a electrolyte and dissociate to give 2 ions. and concentration of ions will be

2. For 0.1 M

, i= 2 as it is a electrolyte and dissociate to give 2 ions, concentration of ions will be

3. For 0.1 M

, i= 2 as it is a electrolyte and dissociate to give 2 ions. and concentration of ions will be

4. For 0.1 M

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be

5. For 0.1 M

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, i= 2 as it is a electrolyte and dissociate to give two ions, concentration of ions will be

Thus as concentration of solute is highest for 0.1 M , the vapor pressure will be lowest.

can you attach the

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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