Chemistry, 23.01.2020 05:31 Jsquad2130

Consider the following inter-conversion, which occurs in glycolysis: fructose-6-phosphate ↔ glucose-6-phosphate keq’ = 1.97 what is δg°’ for the reaction (keq’ measured at 25°c; and r=8.314 j•mol-1•k-1)? (b) if the concentration of fructose-6-phosphate is adjusted to 1.5 m and that of glucose- 6-phosphate is adjusted to 0.50 m, what is δg? (c) why are δg°’ and δg different?

Answers: 3

Show answers

Answers

Answer from: parmer6527p810bw

Explanation:

(a) The relation between $\Delta G^{o}$ and equilibrium constant is as follows.

$\Delta G^{o} = -RT ln K$

As it is given that,

T = $25^{o}C$ = (25 + 273) K = 298 K

K = 1.97

R = 8.314 J/mol K

Hence, putting the given values into the above formula as follows.

$\Delta G^{o} = -RT ln K$

= $-8.314 J/mol K \times 298 K \times ln (1.97)$

= -1679.88 J/mol

= 1.679 kJ/mol (as 1 kJ = 1000 J)

Therefore, the value of $\Delta G^{o}$ is 1.679 kJ/mol.

(b) Expression for $\Delta G$ is as follows.

$\Delta G = \Delta G^{o} + RT ln \frac{\text{Glucose-6-phosphate}}{\text{Fructose-6-phosphate}}$

= $-1679.88 J/mol + 8.314 J/mol K \times 298 K \times \n \frac{0.5}{1.5}$

= -4401.8 J/mol

= 44.01 kJ/mol

Hence, the value for $\Delta G$ is 44.01 kJ/mol.

(c) The value of both $\Delta G$ and $\Delta G^{o}$ are different because $\Delta G$ is measured at any concentration whereas $\Delta G^{o}$ is measured at equilibrium concentration.

Answer from: Quest

Alpha particles have positive charge, beta particles have negative charge, and answer 4 just doesn’t make sense. thus, you are left with only one possible answer.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Another question on Chemistry

Chemistry, 21.06.2019 17:30

Idon’t understand this page, can someone ?

Answers: 1

Answer

Chemistry, 22.06.2019 05:30

What royal scientist used the 29th day of frozen vapor to encounter elements for mastering new culinary creations?

Answers: 1

Answer

Chemistry, 22.06.2019 08:30

The characteristic of two different types of reactions are shown below. reaction a: electrons are gained by the atoms of an element. reaction b: protons are lost by the atom of and element. which statement is true about the atoms of the elements that participate in the two reactions? a: their identity changes in both reaction a and b. b: their identity changes in reaction a but not b. c: their identity changes in reaction b but not a. d: their identity remains the same.

Answers: 1

Answer

Chemistry, 22.06.2019 08:30

Which change in temperature is the smallest? a change of 1 thomson degree a change of 1 kelvin degree a change of 1 fahrenheit degree a change of 1 celsius degree

Answers: 1

Answer

You know the right answer?

Consider the following inter-conversion, which occurs in glycolysis: fructose-6-phosphate ↔ glucose...

Questions