Calculate the volume in liters of a 0.360 mol/l barium acetate solution that contains 100.g of barium acetate (ba(c2h3o2)2) . round your answer to 3 significant digits.

1.08 liters is the volume of 100 g of Ba(CH₃COO)₂

Explanation:

This data is a sort of concentration (Molarity) → 0.360 M [Ba(CH₃COO)₂]

It means that 0.36 moles of solute are contained in 1L of solution.

We should determine the moles of salt, that corresponds to 100 g of solute.

Mass / Molar mass

Ba(CH₃COO)₂ molar mass = 255.3 g/m

100 g / 255.3 g/m = 0.391 moles

So, we can apply a rule of three to calculate the volume of salt.

0.360 moles of solute are contained in 1L of solution

0.391 would be contained in (0.391 .1) / 0.360 = 1.08 liters

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