Given the following, what is the equilibrium constant for the reaction: 2 a + 3 d â 3 c + 2 b? i: 2 a â 2 b, k = 1x105 ii: c â d, k = 2x103 a) 1x10â10 b) 1x10â5 c) 5x101 d) 2x108 e) 8x109 f) 8x1014

K= 1.25*10⁻⁵  (any of the options) , but if the problem's statement is wrong and D → C, K₂ =  [C]/[D] = 2*10³ then K= 8*10¹⁴ (option F)

Explanation:

for

2 A + 3 D → 3 C + 2 B

K= [C]³*[B]² /([A]²*[D]³) = ([B]/[A])²* ([C][/D])³

where

2 A → 2 B , K₁ = [B]²/[A]² = ([B]/[A])² =1*10⁵

and

C → D, K₂ =  [D]/[C] = 2*10³

therefore

K=K₁* (1/K₂)³=K₁/K₂³ = 1*10⁵ / (2*10³)³ = 1.25*10⁻⁵

K= 1.25*10⁻⁵

but if the problem's statement is wrong and

D → C, K₂ =  [C]/[D] = 2*10³

then

K=K₁*K₂³=K₁*K₂³ = 1*10⁵ * (2*10³)³ =8*10¹⁴

K= 8*10¹⁴

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong