The gas in a 250. ml piston experiences a change in pressure from 1.00 atm to 4.45 atm. what is the new volume (in ml) assuming the moles of gas and temperature are held constant

56.2 mL

Explanation:

Given data

Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.00 atm × 250 mL/ 4.45 atm

V₂ = 56.2 mL

particle   p is an electron and particle q is a neutron

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