According to the following reaction, how many grams of hydrogen peroxide (
h
2
o
2
) are necessary to form 0.182 moles oxygen gas?
hydrogen peroxide (
h
2
o
2
) (aq)
→
water (l) + oxygen (g)

12.4 g

Explanation:

Let's consider the following balanced equation.

H₂O₂(aq) → H₂O(l) + 0.5 O₂(g)

The molar ratio of H₂O₂ to O₂ is 1:0.5. The moles of H₂O₂ required to form 0.182 moles of O₂ are:

0.182 mol O₂ × (1 mol H₂O₂/ 0.5 mol O₂) = 0.364 mol H₂O₂

The molar mass of H₂O₂ is 34.01 g/mol. The mass of H₂O₂ corresponding to 0.364 moles is:

0.364 mol × 34.01 g/mol = 12.4 g

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.