Molecular iodine, i2 (g), dissociates into iodine atoms at 545k with a first order rate constant of 0.344 1/s. if you start with 0.054 m i2 at this temperature how much will remain after 5.16 s?

0.00915 M of remain after 5.16 seconds.

Explanation:

Using integrated rate law for first order kinetics as:

Where,  

is the concentration at time t

is the initial concentration

Given that:

The rate constant, k = s⁻¹

Initial concentration = 0.054 M

Final concentration = ? M

Time = 5.16 s

Applying in the above equation, we get that:-

0.00915 M of remain after 5.16 seconds.

58750.08068 is the answer i think