Which one of the following substances is more likely to dissolve in benzene(c6h6)? a) naclb) ccl4c) nh3d) ch3ch2ohe) ehbr

B. CCl₄

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Hence , from the question ,

Benzene is a non - polar compound , i.e. does not separate out into poles , and hence , it will get dissolved into the CCl₄ , as it is too non - polar in nature , according to the above theory of solubility.

Hence, from the question,

Benzene will dissolve in CCl₄ .

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

a is the correct answer