The ionic compound, na3po4, will fully dissolve in water. if 19.68 g is dissolved in 504.0 ml water, find the following ion concentrations.

part 1: the concentration of the na+ is:

part 2: the concentration of the po43- is:

The concentration of is 0.72 M and 0.24 M respectively.

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of sodium phosphate = 19.68 g

Molar mass of sodium phosphate = 164 g/mol

Volume of solution = 504.0 mL

Putting values in above equation, we get:

We are given:

An ionic compound having chemical formula . Its ionization reaction follows:

1 mole of sodium phosphate produces 3 moles of sodium ions and 1 mole of phosphate ions

Concentration of sodium ions =

Concentration of phosphate ion =

Hence, the concentration of is 0.72 M and 0.24 M respectively.

it is a solid

explanation: