When sodium is put in water, it quickly reacts according to the following equation: 2 na (s) + 2h_2o (ii) > 2naoh (aq) + h_2 (g)
if 4.52 moles of na react with an excess of water, how many grams of h_2 are formed?

4.52g of H2 will be produced

Explanation:Please see attachment for explanation

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

i believe the answer is 5,000