Rank the following five elements by ionization energy rank from highest to lowest ionization energy. to rank items as equivalent, overlap them

highest to lowest

s, cl, si, mg, na

Cl, S, Si, Mg, Na

Explanation:

The ionization energy is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom. In the periodic table, it increases from left to right and from bottom to top.

All the elements are in the same period, so the ionization energy is higher in higher groups.

S is in Group 16Cl is in Group 17Si is in Group 14Mg is in Group 2Na is in Group 1

The order from highest to lowest ionization energy is:

Cl, S, Si, Mg, Na

The reaction 2kalsi3o8 + 2(h+ + hco3-) + h2o  →  al2si2o5(oh)4 + 2k+ + 2hco3- + 4sio2 shows that feldspar kalsi3o8 is chemically altered by hydrolysis to form chalky-looking clay mineral kaolinite al2si2o5(oh)4. the chemical breakdown of potassium feldspar due to exposure to acidic water results to the mineral binding with the water molecule to become kaolinite with silica and potassium and bicarbonate ions in solution.

Definitely 25.3 degrees celsius