What pressure will be needed to lwave the vloume of 77.4l ay helium at 98.ok pa to a vloume of 60.0l

P₂ = 126.42 kpa

Explanation:

Given data:

Initial volume = 77.4 L

Initial pressure = 98.0 Kpa

Final volume = 60.0 L

Final pressure = ?

Solution:

Formula:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = Initial volume

P₂ = Final pressure

V₂ = Final volume

Now we will put the values in formula.

P₁V₁ = P₂V₂

98.0 kpa × 77.4 L  = P₂× 60.0 L

7585.2 Kpa.L = P₂× 60.0 L

P₂= 7585.2 Kpa.L/ 60.0 L

P₂ = 126.42 kpa

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.

the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.