When barium chloride reacts with potassium sulfate, barium sulfate and potassium chloride arc produced. the balanced equation for this reaction is: bacl2(aq) + k2so4(aq) → baso4(s) + 2kcl(aq) if 2 moles of potassium sulfate react, the reaction consumes of barium chloride. the reaction produces of barium sulfate and of potassium chloride.

Ratio between the reactants is 1:1, so if 2 moles of potassium sulfate react, The reaction consumes 2 moles of barium chloride

The reaction produces 2 moles of barium sulfate ( ratio is 1:1) and 4 moles of potassium chloride. (Ratio with this is 2:4)

Explanation:

This is the reaction:

BaCl₂(aq) + K₂SO₄(aq) → BaSO₄(s) + 2KCl(aq)

Ratio between the reactants is 1:1, so if 2 moles of potassium sulfate react, The reaction consumes 2 moles of barium chloride

The reaction produces 2 moles of barium sulfate ( ratio is 1:1) and 4 moles of potassium chloride. (Ratio with this is 2:4)

The reaction consumes 2.0 moles of barium chloride. The reaction produces 2.0 moles of barium sulfate and 4.0 moles of potassium chloride.

Explanation:

Step 1: Data given

2 moles of potassium sulfate react

Step 2: The balanced equation

BaCl2(aq) + K2SO4(aq) → BaSO4(s) + 2KCl(aq)

Step 3: Calculate moles

For 1 mol BaCl2 we need 1 mol K2SO4 to produce 1 mol Ba2SO4 and 2 moles KCl

For 2 moles K2SO4 we need 2 moles BaCl2 to produce 2 moles BaSO4 and 4 moles KCl

The reaction consumes 2.0 moles of barium chloride. The reaction produces 2.0 moles of barium sulfate and 4.0 moles of potassium chloride.

the ratio of the conjugate base to the acid required to attain the desired ph.