How many atoms are there in 34.02 grams of hydrogen peroxide

There are 6.022 *10^23 atoms in 34.02 grams hydrogen peroxide

Explanation:

Step 1: Data given

Hydrogen peroxide = H2O2

Mass of H2O2 = 34.02 grams

Molar mass of H2O2 = 34.01 g/mol

Number of Avogadro = 6.022 *10^23 / mol (This means we have 6.022 *10^23 particles per 1 mol)

Step 2: Calculate moles H2O2

Moles H2O2 = mass H2O2 / molar mass H2O2

Moles H2O2 = 34.02 grams / 34.01 g/mol

Moles H2O2 = 1.000 moles

Step 3: Calculate atoms in H2O2

Number of atoms = number of moles * number of Avogadro

Number of atoms = 1.000 moles * 6.022 *10^23 / mol

Number of atoms = 6.022 *10^23 atoms

There are 6.022 *10^23 atoms in 34.02 grams hydrogen peroxide