If an aluminum skillet with 10.0 inch diameter weighs 3.00 pounds, what volume of aluminum does it contain? (the density of aluminum is 2.70g/cm3, 1.00 pound = 453.6g)

The answer to your question is 504 cm³

Explanation:

Data

diameter = 10 in

mass = 3 pounds

density = 2.7 g/cm³

1 pound ----- 453.6 g

Process

1.- Convert pounds into grams using proportions

                             1 pound ---------------  453.6 g

                             3 pounds ------------   x

                             x = (3 x 453.6) / 1

                             x = 1360.8 g

2.- Calculate the volume of the skillet

Formula

density =

Solve per volume

Substitution

Simplification and result

      volume = 504 cm³

the answer is learned

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