Suppose a cobalt atom in the oxidation state formed a complex with two bromide anions and four ammonia molecules. write the chemical formula of this complex.

Complete Question:

Suppose a cobalt atom in the +3 oxidation state formed a complex with two bromide (Br-) anions and four ammonia (NH3) molecules. write the chemical formula of this complex.

[Co(NH₃)₄]⁺Br₂

Explanation:

The cobalt atom with +3 oxidation is represented as Co⁺³, and if it's bonded to two bromide ions, and four ammonia molecules. The molecules that are bonded to the metal atom (Co) are called complexing agents.

In the representation, we first put the molecules that surround the metal atom, forming an anion with the oxidation of the metal:

[Co(NH₃)₄]⁺³

Then, the ions are put in the formula. Because there are two bromides ion, each one with 1 minus charge, only 2 plus charged will be neutralized, and the complex will be:

[Co(NH₃)₄]⁺Br₂

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

lol idk man i guess u gotta ask bill nye the science guy