What is the concentration of no3- ions in a solution prepared by dissolving 30 g of ca(no3)2 in enough water to produce 300. ml of solution. a.0.305 m b.0.609 m c.0.806 m d. none of these

d. None of these

Explanation:

The molar mass of Ca(NO₃)₂ is 164.088 g/mol. The moles corresponding to 30 g are:

30 g × (1 mol/164.088 g) = 0.183 mol

There are 2 moles of NO₃⁻ in 1 mole of Ca(NO₃)₂. The moles of NO₃⁻ in 0.183 moles of Ca(NO₃)₂ are 2 × 0.183 mol = 0.366 mol

The molar concentration of NO₃⁻ is:

0.366 mol/0.300 L = 1.22 M

i'm pretty sure its b i might be wrong though!

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