Aglass containing 200.0 g of h2o at 20.0°c was placed in a refrigerator. the water loses 11.7 kj as it cools to a constant temperature. what is its new temperature? the specific heat of water is 4.184 j/g·°c.

Final temperature = 6.00 °C

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

Where,  

 is the enthalpy change

m is the mass

C is the specific heat capacity

 is the temperature change

Thus, given that:-

Mass of water = 200.0 g

Specific heat = 4.18 J/g°C

Let final temperature be x °C

= -11.7 kJ  (Negative sign as heat is lost)

Also, 1 kJ = 1000 kJ

= -11700 J

So,  

Final temperature = 6.00 °C

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