How many grams of water are required to form 9.00 moles of tio2 according to the reaction described by
the following equation: ticl4 + 2h2o → tio2 + 4hci.
a. 36 g h2o
b. 324 g h2o
c. 359 g h2o
d. 719 g h2o

324 g of H₂O - Option B.

Explanation:

TiCl₄ + 2H₂O → TiO₂ + 4HCI

1 mol of TiO₂ needed 2 mol of water to be produced.

9 moles of TiO₂ would need 18 mol of water, to be produced (2x9)

1 mol of water weighs 18 g

18 mol of water weigh (18 . 18)/1 = 324 g

right

explanation:

neutrons are in the middle of the atom and the electrons, which are much smaller.