Apply the henderson-hasselbalch equation to calculate the ch3nh3'/ ch3nh2 ratio in water buffered at ph 7.

Explanation:

As we know that:-

For :-

pH = 7

Also, pH + pOH = 14  

So, pOH = 14 - 7 = 7

Considering the Henderson- Hasselbalch equation for the calculation of the pOH of the basic buffer solution as:

So,  

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o