Write a balanced equation of reaction. solid potassium chlorate is heated to form solid potassium chloride and oxygen gas. express your answer as a chemical equation. identify all of the phases in your answer.

2KClO3(s) → 2KCl(s) + 3O2(g)

Explanation:

Step 1: Data given

Solid potassium chlorate = KClO3(s)

solid potassium chloride = KCl

oxygen gas = O2

Step 2: The balanced equation

KClO3(s) → KCl + O2

On the left side we have 3x O, on the right side we have 2x O

To balance the amount of O we have to multiply KClO3 (on the left side) by 2 and multiply O2 on the right side by 3

2KClO3(s) → KCl(s) + 3O2(g)

On the left we have 2x K, on the right we have 1x K.

To balanced the amount of K we have to multiply KCl on the right side by 2

Now the equation is balanced

2KClO3(s) → 2KCl(s) + 3O2(g)

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explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.