How many grams of iron(iii) oxide (fe(oh)3) may theoretically be produced from 85.0 g fecl3?

56.0 g

Explanation:

Calculation of the moles of as:-

Mass = 85.0 g

Molar mass of = 162.2 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the reaction:-

1 mole of on reaction forms 1 mole of

Also,

0.52404 mole of on reaction forms 0.52404 mole of

Moles of  = 0.52404 moles

Molar mass of  = 106.867 g/mol

Mass = Moles*Molar mass = = 56.0 g

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