Asolid mixture consists of 44.2g of kno3 (potassium nitrate) and 7.8g of k2so4 (potassium sulfate). the mixture is added to 130. g of water. if the solution described in the introduction is cooled to 0 ∘c, what mass of kno3 should crystallize? (assume kno3 has a solubility of 14 g solute/ 100 g water

26 g left undisolved  which gives you the amount that would crystallize

Explanation:

Step 1: Data given

A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate).

The mixture is added to 130. g of water

KNO3 has a solubility of 14 g solute/ 100 g water

Step 2: Calculate mass of KNO3 in 130 grams of water

X g of KNO3/ 130 g water= 14 g of KNO3/ 100 g water    

X = 14*1300/100 = 18.2

X= 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water)  

Step 3: Calculate amount KNO3 that will crystallize

Of the 44.2g of KNO3 in 130 g of water at 0 degrees celsiusonly 18.2 can dissolve, this means:

44.2g - 18.2g = 26 g left undisolved  which gives you the amount that would crystallize

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be