2nal + cl2 → 2naci + i2

how many grams of iodine are liberated if 546 g of chlorine react with excess sodium iodide?

(i'm a really busy ap student with a lot of homework. just need the work and answer! )

Mass of iodine = 1954.26 g

Explanation:

Given data:

Mass of chlorine react = 546 g

Mass of iodine produced = ?

Solution:

Chemical equation:

2NaI + Cl₂  →  2NaCl + I₂

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 546 g/71 g/mol

Number of moles = 7.7 mol

Now we will compare the moles of chlorine with iodine.

                     Cl₂          :          I₂

                      1             :          1

                      7.7         :          7.7

Mass of iodine:

Mass = number of moles × molar mass

Mass = 7.7 mol × 253.8 g/mol

Mass = 1954.26 g

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."