Using the equation below, calculate the number of grams of h2o that are formed from the reaction of 34.0 g of nh3.

4nh3 + 3o2 --> 2n2 + 6h2o

54 grams of H₂O

Explanation:

4NH₃ + 3O₂   →   2N₂ + 6H₂O

Ratio is 4:6.

Let's convert the mass of ammonia in moles

Mass / Molar mass = Mol

34 g / 17 g/m = 2 moles

If 4 moles of ammonia are needed to produce 6 mol of water

2 mol of NH₃ will produce ( 2 .6 )/4 = 3 moles

Molar mass water = 18 g/m

Mass = mol . molar mass → 3 m . 18 g/m = 54 grams

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