If 1,079.75 joules of heat are added to 77.75 grams of water, by how many degrees celsius would the water increase? assume water is in the liquid state.

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

Explanation:

Here , q = heat added / removed from the substance

m  = mass of the substance taken

= Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

on transposing ,

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-