Ineed to make this into an ionic equation with state symbols

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

Explanation:

There are three steps you must follow. You must write the:

A. Molecular equation

Pb(NO₃)₂(aq) + 2KI(aq) ⟶ PbI₂(s) + 2KNO₃(aq)

B. Ionic equation

You write all the soluble substances as ions.

Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

The net ionic equation is

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

b.final

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.