Acar on a 25-m2 hydraulic lift platform weighs 15,000 n. if the force on the smaller piston required to lift it is 1/100 its weight, what is the area of the smaller piston?

The area is  2.5 m²

Explanation:

Step 1: Data given

A car has a 25 m² hydraulic lift platform that weighs 15000 N

The smaller piston required a force to lift = 1/100 its weight

Step 2: Calculate the area of the smaller piston

Pressure = Force / Area

F1 / A1 = F2 / A2

⇒ with F1 = weight of the hydraulic lift =  15000 N

⇒ with A1 = area of the hydraulic lift = 25 m²

⇒ with F2 = 1/100 of it's weight = 1500 N

A2 = F2 / (F1/A1)

A2 = 1500 ( 1500/25)

A2 = 2.5

The area is  2.5 m²

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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