Calculate the silver ion concentration in a saturated solution of silver(i)carbonate, ag2co3.
(ksp = 8.1

The silver ion concentration is 2.54 * 10^-4 M

Explanation:

Step 1: Data given

Ksp of Ag2CO3 = 8.1 * 10^-12

Step 2: The balanced equation

Ag2CO3 ⇌  2Ag+ + CO3^2-

Step 3: The initial concentration

Ag2CO3: X M

Ag+: 0M

CO3^2- : 0M

Step 4: The concentration at equilibrium

Ag2CO3: There will react X

Ag+: There will react 2X ⇒ we will have (2X) M

CO3^2-: there will react X ⇒ we will have X M

Step 5:

Ksp = 8.1 * 10^-12 = [Ag+]² * [CO3^2-]

Ksp = 8.1 * 10^-12 = (2x)² * X = 4X³

X = 1.27 * 10^-4

[Ag+] = 2X = 2 *1.27 * 10^-4 = 2.54 * 10^-4 M

The silver ion concentration is 2.54 * 10^-4 M

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons