What is the net ionic equation for the reaction that occurs when aqueous copper(ii) sulfate is added to excess 6-molar ammonia? a. cu2+ + so42¯ + 2 nh4+ + 2 oh¯ > (nh4)2so4 + cu(oh)2 b. cu2+ + 4 nh3 + 4 h2o --> cu(oh)42¯ + 4 nh4+ c. cu2+ + 2 nh3 + 2 h2o --> cu(oh)2 + 2 nh4+ d. cu2+ + 4 nh3 --> cu(nh3)42+ e. cu2+ + 2 nh3 + h2o --> cuo + 2 nh4+

c. 2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

Explanation:

A net ionic equation is a chemical equation that list only the species that are involved in the reaction.

The reaction of ammonia with copper(II) sulfate CuSO₄ in water is:

2NH₃ + 2H₂O  + CuSO₄ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

In an ionic equation, salts are written as ions, that means CuSO₄ must be written as Cu²⁺ + SO₄²⁻. That is:

2NH₃ + 2H₂O  + Cu²⁺ + SO₄²⁻ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

As in a net ionic equation you must list only the species involved in the reaction (The underlined species don't react), the net ionic equation is:

c. 2NH₃ + 2H₂O  + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

I hope it helps!

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i think so it’s will be b yes i believe its