4fe + 3o2 - 2fe2o3 when iron rusts in air, iron (iii) oxide is produced. how many moles of oxygen react with 2.4 moles of iron in the rusting process?

moles of oxygen (O₂) = 1.8 mole

Explanation:

Data Given:

moles of Fe (iron) = 2.4 moles

moles of Oxygen (O₂) = ?

Reaction Given

              4Fe + 3O₂ >  2Fe₂O₃

Solution:

To solve this problem we have to look at the reaction

Reaction Given

                    4Fe    +     3O₂ > 2Fe₂O₃

                   4 mol        3 mol

So if we look at the reaction; 4 mole of iron (Fe) react with 3 moles of oxygen (O₂) in a rusting reaction, then how many moles of oxygen (O₂) will react with 2.4 moles of iron (Fe)

For this apply unity formula

                     4 mole of iron (Fe) ≅ 3 moles of oxygen (O₂)

                    2.4 mole of iron (Fe) ≅ X moles of oxygen (O₂)

By Doing cross multiplication

                  moles of oxygen (O₂) = 3 moles x 2.4 moles / 4 mole

                  moles of oxygen (O₂) = 1.8 mol

2.4 mole of iron (Fe) will react with 1.8 moles of oxygen (O₂)

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