Astudent wishes to prepare 2.00 liters of a 0.100 m kio3 (molecular weight 214). the proper procedure is to weigh out:
(a) 42.8 grams of kio3 and add 2.00 kg of h2o
(b) 42.8 grams of kio3 and add h2o until the final homogeneous solution has a volume of 2.00 l
(c) 21.4 grams of kio3 and add h2o until the final homogeneous solution has a volume of 2.00 l
(d) 42.8 grams of kio3 and add 2.00 liters of h2o
(e) 21.4 grams of kio3 and add 2.00 liters of h2o

B

Explanation:

A. Wrong

The volume of water in 2kg of water might not be 2L

D is correct.

Firstly, we need to know that the number of moles equals the mass over the molar mass. Doing this with the particular data in tie question would give 0.2M.

Hence it is essential that what we get is 0.2M in one liter. But since we are gunning for 2L, adding more than one liter of water would affect the molarity, that is why it now will be 0.1M in 2L

C is wrong

What is prepared here is 0.05M in 2L

B is wrong

What is needed is actually 2L of water and not the total volume of both being 2L

E is wrong