When the chemical equation is balanced what is the ratio of the coefficient of ag(s) to the cofficient of h2o((s)+-(aq)++(aq)→ +(aq)+(g)+(l)a. 1: 1b. 2: 1c. 3: 1d. 3: 2

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

Explanation:

Step 1: Balancing the equation

3 Ag (s) + 4 HNO3 (aq) → 3 AgNO3 (aq) + NO (g) + 2 H2O (l)

3 A g ( s )  +  4N O  ^3-  +  4 H +  → 3 A g + +3NO3- +   + N O  +  2 H 2 O

3 A g ( s )  +  N O  ^3-(aq)  +  4 H +(aq)  → 3 A g +(aq)   + N O(g)  +  2 H 2 O(l)

Step 2: The ratio between Ag(s) and H2O(l)

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

i know insulin is primary but i dont know the others im sorry

explanation: