15.00 ml of a .127 m cacl2 solution are mixed
with25.60 ml of a .137 m
ca(no3)2 solution. what is the
molarconcentration ion in the resulting solution?

The question is incomplete, here is the complete question:

15.00 mL of a 0.127 M solution are mixed  with 25.60 mL of a 0.137 M solution. What is the molar concentration of ions in the resulting solution?

The concentration of calcium and chloride ions in the resulting solution are 0.133 M and 0.266 M respectively.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

where,

are the molarity and volume of the first solution

are the molarity and volume of the second solution

We are given:

Putting all the values in above equation, we get:

The chemical equation for the ionization of calcium chloride follows:

1 mole of calcium chloride produces 1 mole of calcium ions and 2 moles of chloride ions

So, concentration of calcium ion = 0.133 M

Concentration of chloride ions =

Hence, the concentration of calcium and chloride ions in the resulting solution are 0.133 M and 0.266 M respectively.

b) mutualism

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the answer would be a