How many grams of a solution that is 50% by weight naoh
isrequired to make 1 liter of 0.15m naoh solution?

12 g

Explanation:

We want to prepare 1 L of a 0.15 M NaOH solution. The moles of NaOH required are:

0.15 mol/L × 1 L = 0.15 mol

The molar mass of NaOH is 40.00 g/mol. The mass corresponding to 0.15 mol is:

0.15 mol × (40.00 g/mol) = 6.0 g

The starting solution is 50% by weight. The mass of solution that contains 6.0 g of NaOH is:

6.0 g NaOH × (100 g solution/50 g NaOH) = 12 g solution

there all right good

explanation:

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b