During an experiment, the percent yield of calcium chloride from a reaction was 80.34%. theoretically, the expected amount should have been 115 grams. what was the actual yield from this reaction? caco3 + hcl → cacl2 + co2 + h2o

The actual yield from this reaction is 92.39 grams CaCl2

Explanation:

Step 1: Data given

% yield = 80.34 %

Expected amount of Calcium chloride (CaCl2) = 115 grams

Step 2: The balance equation

CaCO3 + 2HCl → CaCl2 + CO2 + H2O

Step 3: Calculate actual yield

% yield = 80.34 % = 0.8034  = actual yield / theoretical yield

actual yield = 0.8034 * 115.0 grams

actual yield = 92.39 grams

The actual yield from this reaction is 92.39 grams CaCl2

i can confirm that 92.39 (or 92.4 on the exam) is correct :)

Explanation:

its mg hope this