Iwill mark you as brainiest, me

the reaction below shows the combustion of butane (c4h10). why is the mole ratio (8 moles co2/2 mol c4h10) used to determine the amount of carbon dioxide (co2) produced when butane (c4h10) combusts in excess oxygen? (1 point)

c4h10 + o2 yields co2 + h2o + heat

butane has a mass that is 4 times greater than co2, so only 2 moles of c4h10 are needed to produce 8 moles of co2.

carbon dioxide has a volume of about one-quarter that of c4h10, so 4 moles of co2 are needed to react with each mole of c4h10.

during combustion, co2 is approximately 4 times more reactive than c4h10, so less c4h10 will participate in the reaction.

when the chemical equation for butane combustion is balanced, 2 moles of c4h10 are needed to produce 8 moles of co2.