How many molecules of aspirin c9h8o4 are there in a 100.0 mg tablet of aspirin

3.34×10³⁰ molecules of C₉H₈O₄

Explanation:

So first determine the molar mass of aspirin:

C₉H₈O₄ → 12 g/mol . 9 + 1g/mol . 8 + 16g/mol . 4 = 180 g/mol

Then convert the mass from g to mg → 180 g . 1000 mg/1g = 180000 mg

= 1.8×10⁵ mg

Then make the rules...

In 1.8×10⁵ mg of aspirin (1 mol) we have 6.02×10²³ molecules

In 100 mg of aspirin, we may have ( 100 . 6.02×10³) / 1.8×10⁵ = 3.34×10³⁰ molecules

increased stability in the completion of fluorine's outer shell.