What particle is needed to complete the following nuclear equation? subscript 25 superscript 56 baseline upper mn right arrow blank plus subscript negative 1 superscript 0 baseline e
a. subscript 27 superscript 56 baseline upper co
b. subscript 25 superscript 27 baseline upper mn
c. subscript 26 superscript 56 baseline upper fe
d. subscript 24 superscript 58 baseline upper cr

The correct option is not provided

Explanation:

The illustration depicted in the question is that of a beta decay where the mass number is not affected but the atomic number is decreased by one (after the loss of an electron).

From the question

⁵⁶₂₅Mn  ⇒ X + ⁰₋₁e

The "X" is the unknown particle needed to complete the reaction

X will be an element that has a mass number of "56" (since beta emission does not affect the mass number) but the atomic number of X will be "24" (because when an electron is lost during a beta decay, the atomic number of the substance undergoing the decay is subtracted by one). Hence, the unknown element will be ⁵⁶₂₄Cr.

The closest to this option is D but the mass number provided is 58 instead of 56.

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate