The half-life of iodine-131 is about 8 days. how much of a 50mg sample will be left in 25 days? write your answer rounded to the nearest tenth.

5.73 mg of the sample will be left in 25 days.

Explanation:

Given that:

Half life = 8 days

Where, k is rate constant

So,  

The rate constant, k = 0.08664 days⁻¹

Time = 25 days

Using integrated rate law for first order kinetics as:

Where,  

is the concentration at time t

is the initial concentration  = 50 mg

So,  

5.73 mg of the sample will be left in 25 days.

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).