An element x atomic number 3,relative atomic number 6.94 and consists of two isotopes of mass numbers 6 and 7 respectively.
what is the mass number of the more abudant isotope of x?

7

Explanation:

Atomic number of X = 3

Atomic mass of X = 6.94 amu

1st isotope atomic mass = 6 amu

2nd isotope atomic mass = 7 amu

Which is more abundant isotope = ?

Explanation:

we know there are two naturally occurring isotopes of given element X, X-6  and X-7.

First of all we will set the fraction for both isotopes

x for the isotopes having mass 6

1-x for isotopes having mass 7

The average atomic mass of X = 6.94 amu

we will use the following equation,

6x + 7 (1-x) = 6.94

6x + 7 - 7x = 6.94

6x- 7x = 6.94 - 7

-1x = -0.06

x= -0.06/-1

x= 0.06

0.06 × 100 = 6%

6% is abundance of X-6 because we solve the fraction x.

now we will calculate the abundance of X-7.

(1-x)

1-0.06 =0.94

0.94 × 100= 94%

94% for X-7.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

it's 3.2 on edge, i just took the test.